3(x-3)=4-2(x+2)

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Solution for 3(x-3)=4-2(x+2) equation: 



3(x-3)=4-2(x+2)

We move all terms to the left:

3(x-3)-(4-2(x+2))=0

We multiply parentheses

3x-(4-2(x+2))-9=0



We calculate terms in parentheses: -(4-2(x+2)), so:

4-2(x+2)

determiningTheFunctionDomain
-2(x+2)+4

We multiply parentheses

-2x-4+4

We add all the numbers together, and all the variables

-2x

Back to the equation:

-(-2x)



We get rid of parentheses

3x+2x-9=0

We add all the numbers together, and all the variables

5x-9=0

We move all terms containing x to the left, all other terms to the right

5x=9

x=9/5

x=1+4/5

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