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3(x-3)+16=2(x+)
We move all terms to the left:
3(x-3)+16-(2(x+))=0
We add all the numbers together, and all the variables
3(x-3)-(2(+x))+16=0
We multiply parentheses
3x-(2(+x))-9+16=0
We calculate terms in parentheses: -(2(+x)), so:We add all the numbers together, and all the variables
2(+x)
We multiply parentheses
2x
Back to the equation:
-(2x)
x+7=0
We move all terms containing x to the left, all other terms to the right
x=-7
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