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3(x-2)=7+(x-9)
We move all terms to the left:
3(x-2)-(7+(x-9))=0
We multiply parentheses
3x-(7+(x-9))-6=0
We calculate terms in parentheses: -(7+(x-9)), so:We get rid of parentheses
7+(x-9)
determiningTheFunctionDomain (x-9)+7
We get rid of parentheses
x-9+7
We add all the numbers together, and all the variables
x-2
Back to the equation:
-(x-2)
3x-x+2-6=0
We add all the numbers together, and all the variables
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
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