(3-2x)/2=(-4x+1)/5

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Solution for (3-2x)/2=(-4x+1)/5 equation: 



(3-2x)/2=(-4x+1)/5

We move all terms to the left:

(3-2x)/2-((-4x+1)/5)=0

We add all the numbers together, and all the variables

(-2x+3)/2-((-4x+1)/5)=0

We calculate fractions


(-2x)/()+(-((-4x+1)*2)/()=0



We calculate terms in parentheses: +(-((-4x+1)*2)/(), so:

-((-4x+1)*2)/(

We multiply all the terms by the denominator


-((-4x+1)*2)



We calculate terms in parentheses: -((-4x+1)*2), so:

(-4x+1)*2

We multiply parentheses

-8x+2

Back to the equation:

-(-8x+2)



We get rid of parentheses

8x-2

Back to the equation:

+(8x-2)



We get rid of parentheses

(-2x)/()+8x-2=0

We multiply all the terms by the denominator


(-2x)+8x*()-2*()=0

We add all the numbers together, and all the variables

(-2x)+8x*()=0

We get rid of parentheses

-2x+8x*()=0

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