3(x-2)=13+2(x+3)

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Solution for 3(x-2)=13+2(x+3) equation: 



3(x-2)=13+2(x+3)

We move all terms to the left:

3(x-2)-(13+2(x+3))=0

We multiply parentheses

3x-(13+2(x+3))-6=0



We calculate terms in parentheses: -(13+2(x+3)), so:

13+2(x+3)

determiningTheFunctionDomain
2(x+3)+13

We multiply parentheses

2x+6+13

We add all the numbers together, and all the variables

2x+19

Back to the equation:

-(2x+19)



We get rid of parentheses

3x-2x-19-6=0

We add all the numbers together, and all the variables

x-25=0

We move all terms containing x to the left, all other terms to the right

x=25

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