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9(x-2)+8=6x+3(-4+x)
We move all terms to the left:
9(x-2)+8-(6x+3(-4+x))=0
We add all the numbers together, and all the variables
9(x-2)-(6x+3(x-4))+8=0
We multiply parentheses
9x-(6x+3(x-4))-18+8=0
We calculate terms in parentheses: -(6x+3(x-4)), so:We add all the numbers together, and all the variables
6x+3(x-4)
We multiply parentheses
6x+3x-12
We add all the numbers together, and all the variables
9x-12
Back to the equation:
-(9x-12)
9x-(9x-12)-10=0
We get rid of parentheses
9x-9x+12-10=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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