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3(x-2)=-2(3-2x)
We move all terms to the left:
3(x-2)-(-2(3-2x))=0
We add all the numbers together, and all the variables
3(x-2)-(-2(-2x+3))=0
We multiply parentheses
3x-(-2(-2x+3))-6=0
We calculate terms in parentheses: -(-2(-2x+3)), so:We get rid of parentheses
-2(-2x+3)
We multiply parentheses
4x-6
Back to the equation:
-(4x-6)
3x-4x+6-6=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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