2y2+6y+28=(y-2)2

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Solution for 2y2+6y+28=(y-2)2 equation: 



2y^2+6y+28=(y-2)2

We move all terms to the left:

2y^2+6y+28-((y-2)2)=0



We calculate terms in parentheses: -((y-2)2), so:

(y-2)2

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We get rid of parentheses

2y^2+6y-2y+4+28=0

We add all the numbers together, and all the variables

2y^2+4y+32=0

a = 2; b = 4; c = +32;
Δ = b2-4ac
Δ = 42-4·2·32
Δ = -240
Delta is less than zero, so there is no solution for the equation

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