3(x-2)-x=-2(3x-1)+5

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Solution for 3(x-2)-x=-2(3x-1)+5 equation: 



3(x-2)-x=-2(3x-1)+5

We move all terms to the left:

3(x-2)-x-(-2(3x-1)+5)=0

We add all the numbers together, and all the variables

-1x+3(x-2)-(-2(3x-1)+5)=0

We multiply parentheses

-1x+3x-(-2(3x-1)+5)-6=0



We calculate terms in parentheses: -(-2(3x-1)+5), so:

-2(3x-1)+5

We multiply parentheses

-6x+2+5

We add all the numbers together, and all the variables

-6x+7

Back to the equation:

-(-6x+7)



We add all the numbers together, and all the variables

2x-(-6x+7)-6=0

We get rid of parentheses

2x+6x-7-6=0

We add all the numbers together, and all the variables

8x-13=0

We move all terms containing x to the left, all other terms to the right

8x=13

x=13/8

x=1+5/8

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