3(x-2)-4(5x-3)=3(x+3)-7

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Solution for 3(x-2)-4(5x-3)=3(x+3)-7 equation: 



3(x-2)-4(5x-3)=3(x+3)-7

We move all terms to the left:

3(x-2)-4(5x-3)-(3(x+3)-7)=0

We multiply parentheses

3x-20x-(3(x+3)-7)-6+12=0



We calculate terms in parentheses: -(3(x+3)-7), so:

3(x+3)-7

We multiply parentheses

3x+9-7

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

-17x-(3x+2)+6=0

We get rid of parentheses

-17x-3x-2+6=0

We add all the numbers together, and all the variables

-20x+4=0

We move all terms containing x to the left, all other terms to the right

-20x=-4

x=-4/-20

x=1/5

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