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3(x-2)-2(2x-3)=5(3-2x)+3
We move all terms to the left:
3(x-2)-2(2x-3)-(5(3-2x)+3)=0
We add all the numbers together, and all the variables
3(x-2)-2(2x-3)-(5(-2x+3)+3)=0
We multiply parentheses
3x-4x-(5(-2x+3)+3)-6+6=0
We calculate terms in parentheses: -(5(-2x+3)+3), so:We add all the numbers together, and all the variables
5(-2x+3)+3
We multiply parentheses
-10x+15+3
We add all the numbers together, and all the variables
-10x+18
Back to the equation:
-(-10x+18)
-1x-(-10x+18)=0
We get rid of parentheses
-1x+10x-18=0
We add all the numbers together, and all the variables
9x-18=0
We move all terms containing x to the left, all other terms to the right
9x=18
x=18/9
x=2
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