2x-38=4(3x-2)

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Solution for 2x-38=4(3x-2) equation: 



2x-38=4(3x-2)

We move all terms to the left:

2x-38-(4(3x-2))=0



We calculate terms in parentheses: -(4(3x-2)), so:

4(3x-2)

We multiply parentheses

12x-8

Back to the equation:

-(12x-8)



We get rid of parentheses

2x-12x+8-38=0

We add all the numbers together, and all the variables

-10x-30=0

We move all terms containing x to the left, all other terms to the right

-10x=30

x=30/-10

x=-3

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