3(x-2)+5(x+3)=15

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Solution for 3(x-2)+5(x+3)=15 equation: 



3(x-2)+5(x+3)=15

We move all terms to the left:

3(x-2)+5(x+3)-(15)=0

We multiply parentheses

3x+5x-6+15-15=0

We add all the numbers together, and all the variables

8x-6=0

We move all terms containing x to the left, all other terms to the right

8x=6

x=6/8

x=3/4

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