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3(1+3r)=-(6r+4)+8r
We move all terms to the left:
3(1+3r)-(-(6r+4)+8r)=0
We add all the numbers together, and all the variables
3(3r+1)-(-(6r+4)+8r)=0
We multiply parentheses
9r-(-(6r+4)+8r)+3=0
We calculate terms in parentheses: -(-(6r+4)+8r), so:We get rid of parentheses
-(6r+4)+8r
We add all the numbers together, and all the variables
8r-(6r+4)
We get rid of parentheses
8r-6r-4
We add all the numbers together, and all the variables
2r-4
Back to the equation:
-(2r-4)
9r-2r+4+3=0
We add all the numbers together, and all the variables
7r+7=0
We move all terms containing r to the left, all other terms to the right
7r=-7
r=-7/7
r=-1
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