-6-2(n-7)=16+2n

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Solution for -6-2(n-7)=16+2n equation: 



-6-2(n-7)=16+2n

We move all terms to the left:

-6-2(n-7)-(16+2n)=0

We add all the numbers together, and all the variables

-2(n-7)-(2n+16)-6=0

We multiply parentheses

-2n-(2n+16)+14-6=0

We get rid of parentheses

-2n-2n-16+14-6=0

We add all the numbers together, and all the variables

-4n-8=0

We move all terms containing n to the left, all other terms to the right

-4n=8

n=8/-4

n=-2

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