3(x-2)+4x=10x(x+1)

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Solution for 3(x-2)+4x=10x(x+1) equation: 



3(x-2)+4x=10x(x+1)

We move all terms to the left:

3(x-2)+4x-(10x(x+1))=0

We add all the numbers together, and all the variables

4x+3(x-2)-(10x(x+1))=0

We multiply parentheses

4x+3x-(10x(x+1))-6=0



We calculate terms in parentheses: -(10x(x+1)), so:

10x(x+1)

We multiply parentheses

10x^2+10x

Back to the equation:

-(10x^2+10x)



We add all the numbers together, and all the variables

7x-(10x^2+10x)-6=0

We get rid of parentheses

-10x^2+7x-10x-6=0

We add all the numbers together, and all the variables

-10x^2-3x-6=0

a = -10; b = -3; c = -6;
Δ = b2-4ac
Δ = -32-4·(-10)·(-6)
Δ = -231
Delta is less than zero, so there is no solution for the equation

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