3x+4=1/2x+5

Solution for 3x+4=1/2x+5 equation:

3x+4=1/2x+5

We move all terms to the left:

3x+4-(1/2x+5)=0


Domain of the equation: 2x+5)!=0

x∈R


We get rid of parentheses

3x-1/2x-5+4=0

We multiply all the terms by the denominator


3x*2x-5*2x+4*2x-1=0

Wy multiply elements

6x^2-10x+8x-1=0

We add all the numbers together, and all the variables

6x^2-2x-1=0

a = 6; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·6·(-1)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{7}}{2*6}=\frac{2-2\sqrt{7}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{7}}{2*6}=\frac{2+2\sqrt{7}}{12}
$