3(x-2)+2=3-2(x+1)

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Solution for 3(x-2)+2=3-2(x+1) equation: 



3(x-2)+2=3-2(x+1)

We move all terms to the left:

3(x-2)+2-(3-2(x+1))=0

We multiply parentheses

3x-(3-2(x+1))-6+2=0



We calculate terms in parentheses: -(3-2(x+1)), so:

3-2(x+1)

determiningTheFunctionDomain
-2(x+1)+3

We multiply parentheses

-2x-2+3

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We add all the numbers together, and all the variables

3x-(-2x+1)-4=0

We get rid of parentheses

3x+2x-1-4=0

We add all the numbers together, and all the variables

5x-5=0

We move all terms containing x to the left, all other terms to the right

5x=5

x=5/5

x=1

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