(2x-4)(x-2)=0

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Solution for (2x-4)(x-2)=0 equation: 



(2x-4)(x-2)=0

We multiply parentheses ..

(+2x^2-4x-4x+8)=0

We get rid of parentheses

2x^2-4x-4x+8=0

We add all the numbers together, and all the variables

2x^2-8x+8=0

a = 2; b = -8; c = +8;
Δ = b2-4ac
Δ = -82-4·2·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{4}=2$

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