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3(x-12)=36-3x
We move all terms to the left:
3(x-12)-(36-3x)=0
We add all the numbers together, and all the variables
3(x-12)-(-3x+36)=0
We multiply parentheses
3x-(-3x+36)-36=0
We get rid of parentheses
3x+3x-36-36=0
We add all the numbers together, and all the variables
6x-72=0
We move all terms containing x to the left, all other terms to the right
6x=72
x=72/6
x=12
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