3(1v+2)+2v=7(1v-1)+9

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Solution for 3(1v+2)+2v=7(1v-1)+9 equation: 



3(1v+2)+2v=7(1v-1)+9

We move all terms to the left:

3(1v+2)+2v-(7(1v-1)+9)=0

We add all the numbers together, and all the variables

3(v+2)+2v-(7(v-1)+9)=0

We add all the numbers together, and all the variables

2v+3(v+2)-(7(v-1)+9)=0

We multiply parentheses

2v+3v-(7(v-1)+9)+6=0



We calculate terms in parentheses: -(7(v-1)+9), so:

7(v-1)+9

We multiply parentheses

7v-7+9

We add all the numbers together, and all the variables

7v+2

Back to the equation:

-(7v+2)



We add all the numbers together, and all the variables

5v-(7v+2)+6=0

We get rid of parentheses

5v-7v-2+6=0

We add all the numbers together, and all the variables

-2v+4=0

We move all terms containing v to the left, all other terms to the right

-2v=-4

v=-4/-2

v=+2

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