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3(x-1)-4=2-5(x+5)
We move all terms to the left:
3(x-1)-4-(2-5(x+5))=0
We multiply parentheses
3x-(2-5(x+5))-3-4=0
We calculate terms in parentheses: -(2-5(x+5)), so:We add all the numbers together, and all the variables
2-5(x+5)
determiningTheFunctionDomain -5(x+5)+2
We multiply parentheses
-5x-25+2
We add all the numbers together, and all the variables
-5x-23
Back to the equation:
-(-5x-23)
3x-(-5x-23)-7=0
We get rid of parentheses
3x+5x+23-7=0
We add all the numbers together, and all the variables
8x+16=0
We move all terms containing x to the left, all other terms to the right
8x=-16
x=-16/8
x=-2
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