2a+(3a-10)=47

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Solution for 2a+(3a-10)=47 equation:



2a+(3a-10)=47
We move all terms to the left:
2a+(3a-10)-(47)=0
We get rid of parentheses
2a+3a-10-47=0
We add all the numbers together, and all the variables
5a-57=0
We move all terms containing a to the left, all other terms to the right
5a=57
a=57/5
a=11+2/5

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