3(x-1)(x+2)=6x

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Solution for 3(x-1)(x+2)=6x equation:



3(x-1)(x+2)=6x
We move all terms to the left:
3(x-1)(x+2)-(6x)=0
We add all the numbers together, and all the variables
-6x+3(x-1)(x+2)=0
We multiply parentheses ..
3(+x^2+2x-1x-2)-6x=0
We multiply parentheses
3x^2+6x-3x-6x-6=0
We add all the numbers together, and all the variables
3x^2-3x-6=0
a = 3; b = -3; c = -6;
Δ = b2-4ac
Δ = -32-4·3·(-6)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-9}{2*3}=\frac{-6}{6} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+9}{2*3}=\frac{12}{6} =2 $

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