(4-3x)/5=(3+7x)/2

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Solution for (4-3x)/5=(3+7x)/2 equation: 



(4-3x)/5=(3+7x)/2

We move all terms to the left:

(4-3x)/5-((3+7x)/2)=0

We add all the numbers together, and all the variables

(-3x+4)/5-((7x+3)/2)=0

We calculate fractions


(-3x)/()+(-((7x+3)*5)/()=0



We calculate terms in parentheses: +(-((7x+3)*5)/(), so:

-((7x+3)*5)/(

We multiply all the terms by the denominator


-((7x+3)*5)



We calculate terms in parentheses: -((7x+3)*5), so:

(7x+3)*5

We multiply parentheses

35x+15

Back to the equation:

-(35x+15)



We get rid of parentheses

-35x-15

Back to the equation:

+(-35x-15)



We get rid of parentheses

(-3x)/()-35x-15=0

We multiply all the terms by the denominator


(-3x)-35x*()-15*()=0

We add all the numbers together, and all the variables

(-3x)-35x*()=0

We get rid of parentheses

-3x-35x*()=0

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