3(x-)=-21+4(x+2

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Solution for 3(x-)=-21+4(x+2 equation: 



3(x-)=-21+4(x+2

We move all terms to the left:

3(x-)-(-21+4(x+2)=0

We add all the numbers together, and all the variables

3x-(-21+4(x+2)=0



We calculate terms in parentheses: -(-21+4(x+2), so:

-21+4(x+2

determiningTheFunctionDomain
4(x+2-21

Back to the equation:

-(4(x+2-21)



We add all the numbers together, and all the variables

3x-(4(x-19)=0



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