22=-y-3(3y-4)

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Solution for 22=-y-3(3y-4) equation: 



22=-y-3(3y-4)

We move all terms to the left:

22-(-y-3(3y-4))=0



We calculate terms in parentheses: -(-y-3(3y-4)), so:

-y-3(3y-4)

We add all the numbers together, and all the variables

-1y-3(3y-4)

We multiply parentheses

-1y-9y+12

We add all the numbers together, and all the variables

-10y+12

Back to the equation:

-(-10y+12)



We get rid of parentheses

10y-12+22=0

We add all the numbers together, and all the variables

10y+10=0

We move all terms containing y to the left, all other terms to the right

10y=-10

y=-10/10

y=-1

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