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3(x+5)=3(1+x)
We move all terms to the left:
3(x+5)-(3(1+x))=0
We add all the numbers together, and all the variables
3(x+5)-(3(x+1))=0
We multiply parentheses
3x-(3(x+1))+15=0
We calculate terms in parentheses: -(3(x+1)), so:We get rid of parentheses
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
3x-3x-3+15=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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