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3(x+5)-3=2(3x+1)
We move all terms to the left:
3(x+5)-3-(2(3x+1))=0
We multiply parentheses
3x-(2(3x+1))+15-3=0
We calculate terms in parentheses: -(2(3x+1)), so:We add all the numbers together, and all the variables
2(3x+1)
We multiply parentheses
6x+2
Back to the equation:
-(6x+2)
3x-(6x+2)+12=0
We get rid of parentheses
3x-6x-2+12=0
We add all the numbers together, and all the variables
-3x+10=0
We move all terms containing x to the left, all other terms to the right
-3x=-10
x=-10/-3
x=3+1/3
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