(x-2)-9=(x/5)+9

Solution for (x-2)-9=(x/5)+9 equation:

(x-2)-9=(x/5)+9

We move all terms to the left:

(x-2)-9-((x/5)+9)=0

We add all the numbers together, and all the variables

(x-2)-((+x/5)+9)-9=0

We get rid of parentheses

x-((+x/5)+9)-2-9=0

We multiply all the terms by the denominator


x*5)+9)-((+x-2*5)+9)-9*5)+9)=0

We add all the numbers together, and all the variables

x*5)+9)-((x-10)+9)-9*5)+9)=0

We add all the numbers together, and all the variables

x*5)+9)-((x=0

Wy multiply elements

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$