3(x+5)-2x+4(x-2)=4x-(x-2)+3x-4

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Solution for 3(x+5)-2x+4(x-2)=4x-(x-2)+3x-4 equation: 



3(x+5)-2x+4(x-2)=4x-(x-2)+3x-4

We move all terms to the left:

3(x+5)-2x+4(x-2)-(4x-(x-2)+3x-4)=0

We add all the numbers together, and all the variables

-2x+3(x+5)+4(x-2)-(4x-(x-2)+3x-4)=0

We multiply parentheses

-2x+3x+4x-(4x-(x-2)+3x-4)+15-8=0



We calculate terms in parentheses: -(4x-(x-2)+3x-4), so:

4x-(x-2)+3x-4

We add all the numbers together, and all the variables

7x-(x-2)-4

We get rid of parentheses

7x-x+2-4

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

5x-(6x-2)+7=0

We get rid of parentheses

5x-6x+2+7=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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