180=(2c+6)+(3c+4)+(1/2c+5)

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Solution for 180=(2c+6)+(3c+4)+(1/2c+5) equation: 



180=(2c+6)+(3c+4)+(1/2c+5)

We move all terms to the left:

180-((2c+6)+(3c+4)+(1/2c+5))=0



Domain of the equation: 2c+5))!=0

c∈R



We multiply all the terms by the denominator


-((2c+6)+(3c+4)+(1+180*2c+5))=0



We calculate terms in parentheses: -((2c+6)+(3c+4)+(1+180*2c+5)), so:

(2c+6)+(3c+4)+(1+180*2c+5)

We add all the numbers together, and all the variables

(2c+6)+(3c+4)+(180*2c+6)

We get rid of parentheses

2c+3c+180*2c+6+4+6

We add all the numbers together, and all the variables

5c+180*2c+16

Wy multiply elements

5c+360c+16

We add all the numbers together, and all the variables

365c+16

Back to the equation:

-(365c+16)



We get rid of parentheses

-365c-16=0

We move all terms containing c to the left, all other terms to the right

-365c=16

c=16/-365

c=-16/365

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