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3(x+4)=x+(x+2)
We move all terms to the left:
3(x+4)-(x+(x+2))=0
We multiply parentheses
3x-(x+(x+2))+12=0
We calculate terms in parentheses: -(x+(x+2)), so:We get rid of parentheses
x+(x+2)
We get rid of parentheses
x+x+2
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
3x-2x-2+12=0
We add all the numbers together, and all the variables
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10
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