3(x+4)=8(x-2)+8

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Solution for 3(x+4)=8(x-2)+8 equation: 



3(x+4)=8(x-2)+8

We move all terms to the left:

3(x+4)-(8(x-2)+8)=0

We multiply parentheses

3x-(8(x-2)+8)+12=0



We calculate terms in parentheses: -(8(x-2)+8), so:

8(x-2)+8

We multiply parentheses

8x-16+8

We add all the numbers together, and all the variables

8x-8

Back to the equation:

-(8x-8)



We get rid of parentheses

3x-8x+8+12=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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