10=6-(-2q)

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Solution for 10=6-(-2q) equation: 



10=6-(-2q)

We move all terms to the left:

10-(6-(-2q))=0



We calculate terms in parentheses: -(6-(-2q)), so:

6-(-2q)

determiningTheFunctionDomain
-(-2q)+6

We get rid of parentheses

2q+6

Back to the equation:

-(2q+6)



We get rid of parentheses

-2q-6+10=0

We add all the numbers together, and all the variables

-2q+4=0

We move all terms containing q to the left, all other terms to the right

-2q=-4

q=-4/-2

q=+2

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