3(x+4)=7+(x-3)

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Solution for 3(x+4)=7+(x-3) equation: 



3(x+4)=7+(x-3)

We move all terms to the left:

3(x+4)-(7+(x-3))=0

We multiply parentheses

3x-(7+(x-3))+12=0



We calculate terms in parentheses: -(7+(x-3)), so:

7+(x-3)

determiningTheFunctionDomain
(x-3)+7

We get rid of parentheses

x-3+7

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We get rid of parentheses

3x-x-4+12=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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