(2y+3)/7=4

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Solution for (2y+3)/7=4 equation: 



(2y+3)/7=4

We move all terms to the left:

(2y+3)/7-(4)=0

We multiply all the terms by the denominator


(2y+3)-4*7=0

We add all the numbers together, and all the variables

(2y+3)-28=0

We get rid of parentheses

2y+3-28=0

We add all the numbers together, and all the variables

2y-25=0

We move all terms containing y to the left, all other terms to the right

2y=25

y=25/2

y=12+1/2

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