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3(x+4)-6=5x+2(x-1)
We move all terms to the left:
3(x+4)-6-(5x+2(x-1))=0
We multiply parentheses
3x-(5x+2(x-1))+12-6=0
We calculate terms in parentheses: -(5x+2(x-1)), so:We add all the numbers together, and all the variables
5x+2(x-1)
We multiply parentheses
5x+2x-2
We add all the numbers together, and all the variables
7x-2
Back to the equation:
-(7x-2)
3x-(7x-2)+6=0
We get rid of parentheses
3x-7x+2+6=0
We add all the numbers together, and all the variables
-4x+8=0
We move all terms containing x to the left, all other terms to the right
-4x=-8
x=-8/-4
x=+2
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