(6x-4)+(10x+1)=103

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Solution for (6x-4)+(10x+1)=103 equation: 



(6x-4)+(10x+1)=103

We move all terms to the left:

(6x-4)+(10x+1)-(103)=0

We get rid of parentheses

6x+10x-4+1-103=0

We add all the numbers together, and all the variables

16x-106=0

We move all terms containing x to the left, all other terms to the right

16x=106

x=106/16

x=6+5/8

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