3(x+4)-2-2=(2x-3)+5

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Solution for 3(x+4)-2-2=(2x-3)+5 equation: 



3(x+4)-2-2=(2x-3)+5

We move all terms to the left:

3(x+4)-2-2-((2x-3)+5)=0

We add all the numbers together, and all the variables

3(x+4)-((2x-3)+5)-4=0

We multiply parentheses

3x-((2x-3)+5)+12-4=0



We calculate terms in parentheses: -((2x-3)+5), so:

(2x-3)+5

We get rid of parentheses

2x-3+5

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

3x-(2x+2)+8=0

We get rid of parentheses

3x-2x-2+8=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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