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3(x+4)+5x=8x-(-12)
We move all terms to the left:
3(x+4)+5x-(8x-(-12))=0
We add all the numbers together, and all the variables
5x+3(x+4)-(8x-(-12))=0
We multiply parentheses
5x+3x-(8x-(-12))+12=0
We calculate terms in parentheses: -(8x-(-12)), so:We add all the numbers together, and all the variables
8x-(-12)
We add all the numbers together, and all the variables
8x+12
Back to the equation:
-(8x+12)
8x-(8x+12)+12=0
We get rid of parentheses
8x-8x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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