If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(z-4)(z+6)=0
We multiply parentheses ..
(+z^2+6z-4z-24)=0
We get rid of parentheses
z^2+6z-4z-24=0
We add all the numbers together, and all the variables
z^2+2z-24=0
a = 1; b = 2; c = -24;
Δ = b2-4ac
Δ = 22-4·1·(-24)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*1}=\frac{-12}{2} =-6 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*1}=\frac{8}{2} =4 $
| r+0.35=6.40 | | 4y-24y2=0 | | 3h+5=22 | | x^2+8=180 | | -4=−4=n-8n−8 | | n^2=5n=6 | | 3+32x=8x-3 | | 30a-7=53 | | 5(4x+8)=-21+41 | | 4+c=(-5) | | 12e-8=40 | | 2+8y=35 | | x^2-5x-56=x2−5x−56=-2x-2−2x−2 | | 4+c=5 | | 27+3x=2(−x+8)−29 | | (7x−3)^2-31=0 | | (7x−3)^2=31 | | 90=x+x | | 3(u+2)-7=2(u-1)+5 | | 155=x^2+11 | | 1/2x−2=32 | | 12x−2=32 | | 12x^2+45x=0 | | x+4(x+15)=40 | | 6x-38=-20 | | x^+8x-3=-2x-3 | | 4(x-1)+3x=-2(x-1) | | X=5,y=4 | | 210=12x-6/3 | | b/68=24445 | | 4(x-1)+3x=2(x-1) | | -54=6(c-8) |