3(x+4(6-x)+24)-10=6212x

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Solution for 3(x+4(6-x)+24)-10=6212x equation: 



3(x+4(6-x)+24)-10=6212x

We move all terms to the left:

3(x+4(6-x)+24)-10-(6212x)=0

We add all the numbers together, and all the variables

3(x+4(-1x+6)+24)-6212x-10=0

We add all the numbers together, and all the variables

-6212x+3(x+4(-1x+6)+24)-10=0

We move all terms containing x to the left, all other terms to the right

-6212x+3(x+4(-1x+6)+24)=10

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