(x+2)/3-(x-1)/2=2+x-(9+x)/2

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Solution for (x+2)/3-(x-1)/2=2+x-(9+x)/2 equation: 



(x+2)/3-(x-1)/2=2+x-(9+x)/2

We move all terms to the left:

(x+2)/3-(x-1)/2-(2+x-(9+x)/2)=0

We add all the numbers together, and all the variables

(x+2)/3-(x-1)/2-(2+x-(x+9)/2)=0

We calculate fractions


x/()+(-3x+3)/()+(-(2+x-(x+9)*3)/()=0



We calculate terms in parentheses: +(-(2+x-(x+9)*3)/(), so:

-(2+x-(x+9)*3)/(

We multiply all the terms by the denominator


-(2+x-(x+9)*3)



We calculate terms in parentheses: -(2+x-(x+9)*3), so:

2+x-(x+9)*3

determiningTheFunctionDomain
x-(x+9)*3+2

We multiply parentheses

x-3x-27+2

We add all the numbers together, and all the variables

-2x-25

Back to the equation:

-(-2x-25)



We get rid of parentheses

2x+25

Back to the equation:

+(2x+25)



We get rid of parentheses

x/()+(-3x+3)/()+2x+25=0

We multiply all the terms by the denominator


x+(-3x+3)+2x*()+25*()=0

We add all the numbers together, and all the variables

x+(-3x+3)+2x*()=0

We get rid of parentheses

x-3x+2x*()+3=0

We add all the numbers together, and all the variables

-2x+2x*()+3=0

We move all terms containing x to the left, all other terms to the right

-2x+2x*()=-3

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