3(x+3)10x+x-1=108

Solution for 3(x+3)10x+x-1=108 equation:

3(x+3)10x+x-1=108

We move all terms to the left:

3(x+3)10x+x-1-(108)=0

We add all the numbers together, and all the variables

x+3(x+3)10x-109=0

We multiply parentheses

30x^2+x+90x-109=0

We add all the numbers together, and all the variables

30x^2+91x-109=0

a = 30; b = 91; c = -109;
Δ = b2-4ac
Δ = 912-4·30·(-109)
Δ = 21361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-\sqrt{21361}}{2*30}=\frac{-91-\sqrt{21361}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+\sqrt{21361}}{2*30}=\frac{-91+\sqrt{21361}}{60}
$