12(x-3)+10x=3(x+2)-4

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Solution for 12(x-3)+10x=3(x+2)-4 equation: 



12(x-3)+10x=3(x+2)-4

We move all terms to the left:

12(x-3)+10x-(3(x+2)-4)=0

We add all the numbers together, and all the variables

10x+12(x-3)-(3(x+2)-4)=0

We multiply parentheses

10x+12x-(3(x+2)-4)-36=0



We calculate terms in parentheses: -(3(x+2)-4), so:

3(x+2)-4

We multiply parentheses

3x+6-4

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

22x-(3x+2)-36=0

We get rid of parentheses

22x-3x-2-36=0

We add all the numbers together, and all the variables

19x-38=0

We move all terms containing x to the left, all other terms to the right

19x=38

x=38/19

x=2

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