3(x+3)-5(2x-4)=2(2x+6)

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Solution for 3(x+3)-5(2x-4)=2(2x+6) equation: 



3(x+3)-5(2x-4)=2(2x+6)

We move all terms to the left:

3(x+3)-5(2x-4)-(2(2x+6))=0

We multiply parentheses

3x-10x-(2(2x+6))+9+20=0



We calculate terms in parentheses: -(2(2x+6)), so:

2(2x+6)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

-7x-(4x+12)+29=0

We get rid of parentheses

-7x-4x-12+29=0

We add all the numbers together, and all the variables

-11x+17=0

We move all terms containing x to the left, all other terms to the right

-11x=-17

x=-17/-11

x=1+6/11

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