3x+3(2-x)=10-3(2+4x)

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Solution for 3x+3(2-x)=10-3(2+4x) equation: 



3x+3(2-x)=10-3(2+4x)

We move all terms to the left:

3x+3(2-x)-(10-3(2+4x))=0

We add all the numbers together, and all the variables

3x+3(-1x+2)-(10-3(4x+2))=0

We multiply parentheses

3x-3x-(10-3(4x+2))+6=0



We calculate terms in parentheses: -(10-3(4x+2)), so:

10-3(4x+2)

determiningTheFunctionDomain
-3(4x+2)+10

We multiply parentheses

-12x-6+10

We add all the numbers together, and all the variables

-12x+4

Back to the equation:

-(-12x+4)



We add all the numbers together, and all the variables

-(-12x+4)+6=0

We get rid of parentheses

12x-4+6=0

We add all the numbers together, and all the variables

12x+2=0

We move all terms containing x to the left, all other terms to the right

12x=-2

x=-2/12

x=-1/6

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