3(x+20)-10=4x-6+x

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Solution for 3(x+20)-10=4x-6+x equation: 



3(x+20)-10=4x-6+x

We move all terms to the left:

3(x+20)-10-(4x-6+x)=0

We add all the numbers together, and all the variables

3(x+20)-(5x-6)-10=0

We multiply parentheses

3x-(5x-6)+60-10=0

We get rid of parentheses

3x-5x+6+60-10=0

We add all the numbers together, and all the variables

-2x+56=0

We move all terms containing x to the left, all other terms to the right

-2x=-56

x=-56/-2

x=+28

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