3(x+2)=x+4x-12

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Solution for 3(x+2)=x+4x-12 equation: 



3(x+2)=x+4x-12

We move all terms to the left:

3(x+2)-(x+4x-12)=0

We add all the numbers together, and all the variables

3(x+2)-(5x-12)=0

We multiply parentheses

3x-(5x-12)+6=0

We get rid of parentheses

3x-5x+12+6=0

We add all the numbers together, and all the variables

-2x+18=0

We move all terms containing x to the left, all other terms to the right

-2x=-18

x=-18/-2

x=+9

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